20x^2=-35x

Solution for 20x^2=-35x equation:

20x^2=-35x

We move all terms to the left:

20x^2-(-35x)=0

We get rid of parentheses

20x^2+35x=0

a = 20; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·20·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*20}=\frac{-70}{40}
=-1+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*20}=\frac{0}{40}
=0
$